ccna 200 301 bookshelf minecraft head

ccna 200 301 bookshelf minecraft head.Figure 6.1 Implementing a Logical Network with a Class C Mask of /25Exercise Case #2C: 255.255.255.192(/26 )In this second case, we are going to use the subnet mask 255.255.255.192 to subnet the network address 192.168.10.0. 192.168.10.0 = network address255.255.255.192 = subnet maskNow to answer those 5 important questions. . How many subnets are there? Because there are 2 1s in 192 (11000000), the answer is 2?=4 subnets. How many host addresses are there in each subnet? There are 6 host bits (11,000,000), so the answer is26-2 = 62 hosts. The answer is 26-2 = 62 hosts.How many hosts are there? Remember we are counting from 0, so the answers are 0, 64, 128, and 192o.What is the broadcast address of each subnet? The value of the next subnet minus 1, which is actually the value obtained by setting all host bits to 1, is the broadcast address. The next subnet of subnet 0 is 64, so the broadcast address of subnet 0 is 63.What are the valid host addresses? They are the values that lie between the subnet address and the broadcast address. The easiest way to find out the host addresses is to write out the subnet and broadcast addresses. This way, you can see the valid hosts at a glance. The following table summarizes the range of valid host addresses in subnets 0, 64, 128, and 192, as well as the broadcast addresses for each subnet.whatever the address class is) can only be /30, because we must leave at least 2 bits for the hosts. Take the default subnet mask for a Class A address: 255.0.0.0. The first byte of this subnet mask is all 1s, i.e., llllllllo If you use the slash character, you need to count the total number of lo255.0.0.0 can be expressed as /8, because there are 8 1s-that is, there are 8 The default subnet mask for a class B network is 255.255.0.0, which is /16, because there are 16 1's.