ccna schedule exam

ccna schedule exam.6.6 Two-Minute Sprint -Review IP Addressing .IP addresses are 32 bits long and are divided into 4 bytes (8 bits), with adjacent bytes separated by periods. This format is known as dotted decimal representation..5 classes IP addresses and their first byte take the following ranges of values: class A (1 ~ 126), class B (128 ~ 191), class C (192 ~ 223).Class D (224.239) and class E (240-254) IP addresses consist of two parts: the network part and the hostportion.The network portion of a Class A address is the first byte, the network portion of a Class B address is the first two bytes, and the network portion of a Class C address is the first three bytes.. The first few bits of the first byte determine the class of the address. class A addresses are prefixed with a 0, class B addresses with a 10, class C addresses with a 110, class D addresses with a 1110, and class E addresses with a 11110. . Each network contains three types of addresses: network addresses, directed broadcast addresses, and host addresses. The first address in the network is the network address, the last address is the directed broadcast address, and all addresses between these two addresses are host addresses.. The importance of the subnet mask is that it points out the network and host parts of the IP address: without the subnet mask, it is impossible to tell whether the IP address is a network address, a directed broadcast address, or a host address.Subnetting . Subnetting allows you to split the addressing space so that you can use it more efficiently. Subnet divisions borrow the first few bits of the host section and use them to create more subnets while keeping the number of host addresses per subnet low. . Subnet masks are 32 bits long and are usually expressed using dotted decimal (such as 255.255.255.0) or network bits (such as /24). In a subnet mask, all network bits must be together and all host bits must be together O 255.0.255.0 is not a valid subnet mask.IP Address Planning . Planning IP addressing for a network requires 6 steps: 1) determining network and host requirements; 2) satisfying host and network requirements; 3) determining subnet masks; 4) determining network addresses; 5) determining directed broadcast addresses; and 6) determining host addresses. . To satisfy network and host requirements, determine how many bits to use to provide the required number of subnets and also determine how many bits to use to satisfy the host address requirements of the largest network segment. When adding these two bits together, the result cannot exceed the default number of bits in the host section.Determining the Type of IP Address . Use the six steps to determine the type of address: 1) list the IP address and subnet mask; 2) find the associated byte in the subnet mask; 3) subtract 256 from the value of the associated byte in the subnet mask to get how much the associated bytes of adjacent subnet numbers differ; 4) list out the network addresses; 5) list their directed broadcast addresses next to each network address; and 6) the host address is the one between the network address and the directed broadcast address.. The directed broadcast address is smaller than the next network address lo