A. ip route 209.165.201.0 255.255.255.224 209.165.202.130
B. ip route 0.0.0.0 0.0.0.0 209.165.200.224
C. ip route 209.165.200.224 255.255.255.224 209.165.202.129 254
D. ip route 0.0.0.0 0.0.0.0 209.165.202.131
Correct Answer: C
ccna hindi pdf download.via Summary (2169856/0), NullOP 172.16.3.0/24,1 successors, FD is 2172416via 172.16.23.2 (2172416/28160),Serial0/0/lP 172.31.12.0/30,1 successors, FD is 2169856via Connected, Serial0/0/0The above output indicates the information of each route entry in the IPv4EIGRP topology table, including the status of the route entry, the successor router, the feasible distance, all feasible successor routers and their announcement distance, etc. The meaning of the status codes for the above output information is described below..282.Cisco Networking Lab CCNA Lab Guide (Release 2) P: stands for Passive,indicating a stable state where the route entry is available and can be added to the routing table. A: stands for Active,the current route entry is not available,it is in the send query state and cannot be added to the routing table. U: stands for Update, the route entry is being updated or waiting for update packet confirmation status. Q: stands for Query, the route entry has not been answered or is waiting for a query packet acknowledgement. R: stands for Reply, the router is generating an answer to the route entry or is waiting for an answer packet acknowledgement. r: stands for reply Status, the flag set when sending a query and waiting for an answer.S: stands for siaStatus,By default after 3 minutes, if the queried route does not receive an answer from its neighbors, the route is set to stuck in active state, indicating that there is a convergence problem in the EIGRP network. In routing mode, you can modify the sia time by using the command timers active-time [time-limit \ disabled], where the unit of time-limit isminutes.The specific meaning of the routing entry P 172.16.4.0/24, 1 successors, FD is 2172416 1 via 172.16.24.2 (2172416/28160), SerialO/1/O in the topology table is that the routing entry 172.16.4.0/24 is in a passive state, and the entry has 1 successor router with a feasible distance of 2172416, an advertised distance of 28160, a next-hop address of 172.16.24.2, and a local exit of SO/1/Oo
A. ip route 209.165.201.0 255.255.255.224 209.165.202.130
B. ip route 0.0.0.0 0.0.0.0 209.165.200.224
C. ip route 209.165.200.224 255.255.255.224 209.165.202.129 254
D. ip route 0.0.0.0 0.0.0.0 209.165.202.131
Correct Answer: C
A. to analyze traffic and drop unauthorized traffic from the Internet
B. to transmit wireless traffic between hosts
C. to pass traffic between different networks
D. forward traffic within the same broadcast domain
Correct Answer: C
A. switchport mode trunk
B. switchport mode dynamic desirable
C. switchport mode dynamic auto
D. switchport nonegotiate
Correct Answer: B
A. transfers a backup configuration file from a server to a switch using a username and password
B. transfers files between file systems on a router
C. transfers a configuration files from a server to a router on a congested link
D. transfers IOS images from a server to a router for firmware upgrades
Correct Answer: D
A. different nonoverlapping channels
B. different overlapping channels
C. one overlapping channel
D. one nonoverlapping channel
Correct Answer: D
Exam Code: 200-301
Exam Duration: 120 minutes
Exam Topics:
Latest Update: 11.19,2024
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