ccna 200 301 bookshelf decorating clipart

ccna 200 301 bookshelf decorating clipart.Answer:How many octets are we interested in? 256-252 = 4,Calculate: 0,4,8,12,16 (the value of the 4th octet). Therefore the subnet is 172.16.45.12o Since the next subnet is 172.16.45.16, the broadcast address is 172.16.45.15oQ: What is the subnet to which the IP address 172.16.88.255/20 belongs? What is the broadcast address for this subnet?A: What is /20? You can't answer this question if you don't know, so do you know what /20 stands for? The /20 is 255.255.255.240, which tells us that the address block size of the 3rd octet is 16. Since there are no bits lent to the subnet mask in the 4th octet, this part is always 0 or 255. ........................................... There you have it. 88 lies between 80 and 96, so the subnet is 80.0,and the broadcast address is 95.255oQuestion:A router receives a packet from an interface with a destination address of 172.16.46.191/26, what does it do with the packet?Answer:Discard it. Do you know the reason? The mask used for 172.16.46.191/26 is 255.255.255.192, the address block size is 64, and the subnet values calculated out include 0, 64, 128, and 192. 191 is the broadcast address for subnet 128, so as a router, all broadcast packets are discarded by default.6.1.7 Subnetting with Class A AddressesThe subnetting of Class A addresses is no different than Class B and Class C, except that Class A addresses can use 24 bits, while Class B can use 16 bits and Class C can use 8 bits.Let's start by looking at all the available masks for Class A addresses.255.0.0.0 (/8) 255.128.0.0 (/9) 255.255.240.0 (/20) 255.192.0.0 (/10) 255.255.248.0 (/21) 255.224.0.0 (/II) 255.255.252.0 (/22) 255.240.0.0 (/12) 255.255.254.0 (/23) 255.248.0.0 (/13) 255.255.255.0 (/24) 255.252.0.0 (/14) 255.255.255.128 (/25)6.1 Subnetting Basis 255.254.0.0 (/15) 255.255.255.192 (/26)