ccna 200 301 bookshelf minecraft

ccna 200 301 bookshelf minecraft.The default subnet mask for a Class B network is 255.255.0.0, which is /16, because there are 16 1s.192.168.10.33 = node address255.255.255.224 = subnet maskFirst you need to determine the subnet address and broadcast address of this IP address. You can arrive at the answer by using question 3 of the first 5 questions: 256-224=32,which gives you 0, 32, 64, etc. Address 33 is between subnets 32 and 64, so it must belong to subnet 192.168.10.32. the next subnet is 64, so the broadcast address of subnet 32 is 63 (the broadcast address of a subnet is always the value of the next subnet minus 1). The valid host address range is 33.62 (the value between the subnet address and the broadcast address). That's too easy!Now let's try another one, still dividing Class C addresses.What is the address of the subnet to which this IP address belongs? What is the broadcast address of this subnet? 256-240=16,yielding 0, 16, 32, 48, etc. Found - this host address is located between subnets 32 and 48, so the subnet address is determined to be 192.168.10.32,and the broadcast address is 47 (the next subnet is 48). The valid host address range is 33. 46 (the value between the subnet address and the broadcast address).Let's make a few more to make sure you can calculate them independently.The node address is 192.168.10.174,the mask is 255.255.255.240,what is the valid host range?The mask is 240, so first you have to calculate 256-240= 16, which is the size of the address block. Start at 0 and keep adding in units of 16 until the result exceeds 174. Start at 0: 0, 16, 32, 48, 64, 64./8 and /15 can only be used for Class A addresses, /16./23 can be used for Class A and Class B addresses, and /24./30 can be used for Class A, Class B, and Class C addresses. This is the primary factor why most businesses use Class A network addresses, as this allows all subnet masks to be used, bringing maximum flexibility to network design.