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ccna 200 301 bookshelf minecraft skin.There are many different ways to subnet a network, and the one that best suits your network needs is the correct one. In a Class C address, there are only 8 bits that can be used to define a host. Remember that the bits used to divide a subnet are borrowed from left to right, not jumping around. This means that the subnet masks that can be used for Class C addresses are shown below.BinaryDecimalCIDR00000000 =0 /24 10000000=128 /25 11000000=192 /26 11100000 =224 /27 11110000 =240 /28 11111000 =248 /29 11111100=252 /30You cannot use /31 or /32, because you have to reserve at least 2 bits to assign the IP address to the host. In the next subsections, I'll teach you another way to divide subnets that will allow you to divide multiple subnets more easily. Believe me, you'll want to divide subnets even faster!Subnetting with Class C addresses: the quick methodAfter you've picked an alternate subnet mask for your network, you want to determine the subnets that this mask will providenumber, the number of valid hosts, and the broadcast address, you only need to answer the following 5 simple questions... How many subnets can this subnet mask constitute? How many valid host addresses are in each subnet? What are the valid subnets?What is the broadcast address of each subnet? . What are the valid host addresses in each subnet? This is where the subdivision of 2 that you were told to understand and remember earlier comes in handy. If you need a hint, you canRefer to the previous article "Understanding the power of 2" for tips. The answers to these 5 important questions are as follows. -How many subnets are there? inches = number of subnets. x is the number of mask bits, or the number of ones. Using 11000000 as an example, 2 1s can provide 2?subnets, or 4 subnets.How many host addresses are in each subnet? The number of hosts in each subnet. y is the number of non-masking bits, or zeros. Take 11000000 for example. 6. 26-2 host addresses are available. which means that there can be 62 hosts in each subnet. You need to subtract two addresses: a subnet address and a broadcast address because these two are not valid host addresses.