ccna 200 301 syllabus of upsc exam 2017

ccna 200 301 syllabus of upsc exam 2017.199.1.1.0/24Figure 6-3-2 VLSM Calculationk 174_____________________________________ Yongqingyi-Ying'erli1 In order to meet a subnet that can accommodate 100 computers, the number of bits of the subnet host bits should meet at least 7 (27-2=126), you can borrow 1 bit from the 8 bits of the host bits as subnet bits, can be divided into 2 subnets, 0 and 1 subnets, namely 199.1.1.0/25 and 199.1 128/25. need to use ip subnet-zero to support all "0" and all "1" subnets, assign the first department the 199.1.1.0/25 subnet with IP addresses ranging from 199.1.1.0-127,199.1.1.0 is the network number of that subnet, 199.1 .1.1.1 is the first available IP address in that subnet, assuming that the eO interface assigned to the router, 199.1.1.127 is the broadcast address for that subnet, and the range of IP addresses available to computers in that subnet is 199 1.2.126.The subnet is a subnet of 199.1.1.0/25, which has been assigned out of 199.1.1.0/25, leaving one subnet 199.1 ? 128/25. This subnet needs to meet the needs of the remaining four departments, considering that the number of computers in one department is 50, and needs to occupy 6 of the 7 host bits of the 199.1.1.128/25 subnet (2 ^ 2 = 62). The first of these is the subnet of 199.1.1.128/26, the IP address range from 199.1.1.128.191, 199.1.1.128 is the network number of the subnet, 199.LL129 is the subnet of the first available IP address. The first available IP address, if assigned to the router's el interface, 199XP1.191 is the broadcast address for that subnet, and the range of IP addresses available to computers in that subnet is 199.1.1.130-190o3 199.1.1.128/25 is divided into two subnets, 199.1.1.128/26 subnet has been assigned out, there is still a subnet 199.Ll.192/26o this subnet needs to meet the needs of the remaining three departments, considering that the number of computers in each department is 10, need to occupy 199.1.1.192/26 subnet 6 bits of the host bit The first of these is the "Ll.192/26" subnet.4 assign the 199.1.1.192/28 subnet to department three for use, the IP address range from 199.1.1.192.207,199.1.1.192 is the network number of the subnet, 199XP1.193 is the first available IP address in the subnet, suppose the e2 interface assigned to the router, 199.1.1.207 is the broadcast address of the subnet, the The range of IP addresses available for computers in the subnet is 199.1 194.206.5 to 199.1 208/28 subnet assigned to department four use, IP address range from 199 1.208.223, 199.1.1.208 is the network number of the subnet, 199.1.1.209 is the first available IP address in the subnet, if the e3 interface assigned to the router, 199.LL223 is the broadcast address of the subnet, the subnet of the computer available IP address range is 199.1.1.210-222o The range of IP addresses available to the computer is 199.1.1.210-222oThe IP address range is from 199.1.1.224 to 239, 199.1.1.224 is the network number of the subnet, 199.1.1.225 is the first available IP address in the subnet, if assigned to the router's e4 interface, 199.1.1.239 is the broadcast address of the subnet, the range of IP addresses available to computers on the subnet is 199.1.1.226.238.