A. ip route 209.165.201.0 255.255.255.224 209.165.202.130
B. ip route 0.0.0.0 0.0.0.0 209.165.200.224
C. ip route 209.165.200.224 255.255.255.224 209.165.202.129 254
D. ip route 0.0.0.0 0.0.0.0 209.165.202.131
Correct Answer: C
ccna 200-301 network simulator ns2 simulator for beginners.192.168.1.0-15 192.168 floppy 16.31 192.168.1.32-47192.168.1.128.143 192.168.1.144.159192.168.1.240-255\67The IP address preceding each line is the network number for that subnet, and the IP address following it is the broadcast address for that subnet; neither may be used. 158 falls within the 192.168.1.144/28 subnet, and the available IP addresses for that subnet are from 145.158,Only option C is correct.31.Solution.AD QUESTION Q: Ethernet connected to router R1 is aggregated as 192.1.144.0/20 to R2,According to the aggregated route, which of the following packet destinations will be forwarded to R1 by router R2 (choose 2)? As long as the destination IP address in the 192.1.144.0/20 subnet packets will be forwarded to R1 by router R2. first to calculate the range of IP addresses in the 192.1.144.0/20 subnet, the network bits of the subnet has 20 bits, the host bits have 12 bits, the host bits are all set to 1 is the broadcast address, which is also the last IP address in the subnet, the IP address is 192.1.144.0 plus the last 12 bits of I, alsoThe IP address that falls within this subnet range (192.1.144.0.192 ? 159.255) is option A and D.32.Solution.BE Question Q: Referring to the diagram, the network connected to R2 has been aggregated to 192.168.176.0/21 and sent to R1,which two packets with destination addresses will be forwarded to R2 by R1 (choose 2)? This question is the same as the previous question, based on the 21-bit mask bits can be inferred in the first 5 bits of the third 8-bit byte is the same, the difference is the next 3 bits, and 176 is written in binary form as 10110000, the network number is the smallest IP address, the broadcast address is the largest IP address, that is, 10110111, into decimal numbers is 183. then the IP subnet in the IP address range is 192.168.176.0.192.168.183.255,which can
A. ip route 209.165.201.0 255.255.255.224 209.165.202.130
B. ip route 0.0.0.0 0.0.0.0 209.165.200.224
C. ip route 209.165.200.224 255.255.255.224 209.165.202.129 254
D. ip route 0.0.0.0 0.0.0.0 209.165.202.131
Correct Answer: C
A. to analyze traffic and drop unauthorized traffic from the Internet
B. to transmit wireless traffic between hosts
C. to pass traffic between different networks
D. forward traffic within the same broadcast domain
Correct Answer: C
A. switchport mode trunk
B. switchport mode dynamic desirable
C. switchport mode dynamic auto
D. switchport nonegotiate
Correct Answer: B
A. transfers a backup configuration file from a server to a switch using a username and password
B. transfers files between file systems on a router
C. transfers a configuration files from a server to a router on a congested link
D. transfers IOS images from a server to a router for firmware upgrades
Correct Answer: D
A. different nonoverlapping channels
B. different overlapping channels
C. one overlapping channel
D. one nonoverlapping channel
Correct Answer: D
Exam Code: 200-301
Exam Duration: 120 minutes
Exam Topics:
Latest Update: 11.19,2024
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