A. ip route 209.165.201.0 255.255.255.224 209.165.202.130
B. ip route 0.0.0.0 0.0.0.0 209.165.200.224
C. ip route 209.165.200.224 255.255.255.224 209.165.202.129 254
D. ip route 0.0.0.0 0.0.0.0 209.165.202.131
Correct Answer: C
ccna security 640-554 pdf free download.At this point, one more subnet is left. You can assign it to the last segment, but this segment requires only 30 host addresses, and subnet mask/26 provides 62 host addresses, so it is not optimal. If you wish, you can go back to step 4 and repeat the subnetting process for this subnet. Subnet Mask/27 ( 255.255.255.224) gives 30 host addresses to the subnet and further divides the remaining subnet 192.168.1.192/26 into two subnets: 192.168.1.192/27 and 192.168.1.224/27. In this example, there is one remaining subnet that can be used to support future expansion! As you can see, a very efficient IP addressing design can be developed using VLSM.Space should be reserved for expansion of each subnet. For example, in the previous example, using subnet mask/27 in subnet 192.168.1.192/26 would further divide it into two subnets, each containing 30 host addresses. With this addressing scheme, when a segment containing 30 hosts needs to be expanded, a portion of the network must be readdressed, which is not an interesting task.Exam Essentials Keep in mind the 6 steps for performing VLSM and read the next two VLSM examples in detail.1. VLSM Example 1Once you understand the basic steps for performing VLSM, look at a more complex example, as shown in Figure 7.2. In this example, given a Class C network 192.168.2.0/24, your task is to use VLSM to meet the following requirements: no more than 30 hosts in each remote site (seven in total), although this does not take into account future expansion; the links between the central site router and the remote site routers are point-to-point connections.The largest segments need to be handled first, and they are the remote sites containing 30 hosts. To provide 30 host addresses, the subnet mask 225.255.255.224 (/27) needs to be used, which will create the following subnets: 192.168 20/27, 192.168 232/27, 192.168.2.64/27, 192.168.2.96/27, 192.168.2.128/27, 192.168.2.160/27, 192.168.2.160/27. 192.168.2.160/27, 192.168.2.192/27, and 192.168.2.224/27. Subnet 0 is assumed to be available here.Remote Router A 30 hostsRemote Router B 30 hostsRemote router C 30 hostsTwo hosts Remote router D Central router 30 hosts
A. ip route 209.165.201.0 255.255.255.224 209.165.202.130
B. ip route 0.0.0.0 0.0.0.0 209.165.200.224
C. ip route 209.165.200.224 255.255.255.224 209.165.202.129 254
D. ip route 0.0.0.0 0.0.0.0 209.165.202.131
Correct Answer: C
A. to analyze traffic and drop unauthorized traffic from the Internet
B. to transmit wireless traffic between hosts
C. to pass traffic between different networks
D. forward traffic within the same broadcast domain
Correct Answer: C
A. switchport mode trunk
B. switchport mode dynamic desirable
C. switchport mode dynamic auto
D. switchport nonegotiate
Correct Answer: B
A. transfers a backup configuration file from a server to a switch using a username and password
B. transfers files between file systems on a router
C. transfers a configuration files from a server to a router on a congested link
D. transfers IOS images from a server to a router for firmware upgrades
Correct Answer: D
A. different nonoverlapping channels
B. different overlapping channels
C. one overlapping channel
D. one nonoverlapping channel
Correct Answer: D
Exam Code: 200-301
Exam Duration: 120 minutes
Exam Topics:
Latest Update: 11.19,2024
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