ccna secuirty required ccnp router and switch

ccna secuirty required ccnp router and switch.7. How many host addresses does each subnet contain when using the subnet mask 255.255.255.192 in a Class B network? A. 30 B. 62 C. 126 D. 254Determine the type of IP address 8. Given the addressing information 192.168.37.192/25,what type of address is this? A. network address B. directed broadcast address C. host address 9. Given the addressing information 172.17.16.255/23, what type of address is this? A.Network address B.Directed broadcast address C.Host address 10.Given the addressing information 10.0.8.0/22,what type of address is this? A.Network address B.Directed broadcast address C.Host address6.8 Answers to Self-Test QuestionsReview IP AddressingA is true for Class C networks; C is true only for Class A and Class B networks that are subnetted; D is true for Class C networks as well as Class A and Class B networks that are subnetted.A, B, and C are not correct.Subnetting 3. co255.255.254.0 is a valid subnet mask (all 1's together and all 0's together). the 1's in A are not together; B is an inverted subnet mask that reverses the network and host bits; and the 4th byte of D is an invalid value.4. a subnet mask determines whether an IP address is a network address, a host address, or a directed broadcast address.IP Address Planning 5. The default subnet mask for BoC class networks contains 24 network bits. This example borrows one host bit, and 2] = 2 subnets. a, c, and d are incorrect. 6. Bo has 3 host bits,23 =8,so there are 8 addresses per subnet, but two (the network address and the directed broadcast address) cannot be used for host devices, so there are 6 host addresses. You can also subtract 248 from 256,to get 8 addresses per subnet,but the first and last addresses are reserved.A,C and D are not correct. 7. Bo has 7 host bits, 27 = 64, so there are 64 addresses per subnet, but two (the network address and the directed broadcast address) cannot be used for host devices, so there are 62 host addresses. You can also subtract 192 from 256 to get 64 addresses per subnet, but the first and last addresses cannot be used, so the answer is 62. a, c, and d are incorrect.Determining the type of IP address 8. co This Class C network has one subnet bit, so there are two subnets: 192.168.37.0 and 192.168.37.128,where the host address of the first subnet is 192.168.37.129.192.168.37.254,so 192.168.37.192 is a host address. A is correct for 192.168.37.0 and 192.168.37.128; B is correct for 192.168.37.127 and 192.168.37.255. 9. co The third byte of the adjacent subnet number differs by 2. 172.17.16.255 is a host address for the subnet to which it belongs 172.17.16.1.172.17.17.254. a is correct for 172.17.16.0; b is correct for 172.17.17.255. 10. ao The 3rd byte of adjacent subnet numbers differs by 4 o10.0.8.0 is a network address; other network addresses include 10.0.0.0, 10.0.0.