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ccna salary per hour.In step 5, list the directed broadcast address next to each subnet number. In step 6, list out the host address of each subnet. Don't forget that the directed broadcast address is 1 less than the next subnet number, and all IP addresses between the network address and the directed broadcast address are host addresses. Table 6.9 shows the results after completing steps 5 and 6.Table 6.9 Network Address, Directed Broadcast Address, and Host Address in 192.168.1.0/27From Table 6.9, 192.168.1.37 is a host address because it is located in the host address range of subnet 192.168.1.32/27within the subnet 192.168.1.32/27.Exam Essentials When taking the CCNA exam, instead of creating the entire table, simply list to such a subnet number: it is greater than the IP address of the type to be judged. Then, list the directed broadcast addresses and host addresses for the last three subnets so that you know the answers to the exam questions. In the previous example, these three subnets are 192.168.1.0, 192.168.1.32, and 192.168.L64o6.4.3 Example of determining the type of IP address 2To help illustrate the 6 steps, look at another example. In step 1, the following addresses and subnet masks are given: 192.168.1.132255.255.255.192 (/26), which is a Class C address. Don't forget the trick mentioned earlier: if the last byte of the IP address is an even number, it is either a network address or a host address, and not a directed broadcast address.In step 2, you need to find the relevant byte in the subnet mask, in this case the last byte. For Class C networks, the correlation byte is always the last byte. The value of this byte is 192, which indicates that the first two bits of the byte are the network part and the last 6 bits are the host part. In step 3, it is necessary to determine how much the neighboring subnet numbers differ. To do this, subtract 256 from the value of the relevant byte in the subnet mask: 256 - 192 = 64O Accordingly, the adjacent subnet numbers differ by 64, and each subnet contains 64 addresses: a network address, a directed broadcast address, and 62 host addresses. Since the relevant byte is the 4th byte, the 4th byte of the adjacent subnet number differs by 64.In step 4, the subnet numbers are listed. In this example, there are 4 subnets: 192.168.1.0, 192.168.1.64, 192.168.1.128, and 192.168.1.192. In the correlation byte, 2 bits are used to divide the subnets, and the other 6 are used to represent the host addresses. When using 2 bits to divide a subnet, 4 subnets are obtained (2 2 =4), while using 6 bits to represent host addresses provides 64 addresses ( 26 =64).